X^2+2x-4.5=0

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Solution for X^2+2x-4.5=0 equation: 



X^2+2X-4.5=0

a = 1; b = 2; c = -4.5;
Δ = b2-4ac
Δ = 22-4·1·(-4.5)
Δ = 22
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{22}}{2*1}=\frac{-2-\sqrt{22}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{22}}{2*1}=\frac{-2+\sqrt{22}}{2}
$

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